This is a fantastic deep-dive! Let’s answer your question clearly and technically:


βœ… Question Recap:

If I read a 1 GB CSV file or a 1 GB Hive table into a DataFrame β€”
❓ Does defaultParallelism apply?
❓ How are tasks created and executed in this case?


πŸ”§ Short Answer:

No, defaultParallelism does not directly control how Spark parallelizes file reads.

Here’s how it actually works:

Source TypePartitioning Behavior
CSV / JSON / Parquet (from HDFS/S3)Spark splits files into input splits using HDFS block size or internal logic
Hive TablesSpark uses the number of underlying file splits or partitions (if the table is partitioned)
DefaultParallelismApplies only when no better partitioning info is available, e.g., sc.parallelize()

🧠 Internal Mechanics – Step by Step

1. Reading a CSV file (e.g., 1 GB)

df = spark.read.csv("/path/to/file.csv")
  • Spark internally uses Hadoop InputFormat to split this file into input splits.
  • If the file is in HDFS and the block size is 128 MB, you’ll likely get:
    • ~8 input splits β†’ 8 tasks
  • Each input split becomes one task in the initial stage (Stage 0).

You can check this via:

df.rdd.getNumPartitions()

➑️ So, tasks = input splits, not controlled by defaultParallelism.


2. Reading a Hive Table

df = spark.sql("SELECT * FROM my_table")
  • Spark reads the underlying storage format (ORC, Parquet, etc.)
  • If the table is partitioned, Spark will read files per partition.
  • Number of files and their sizes decide how many tasks will run.

➑️ If the table has 10 partitions and each is stored in a 100MB file, you’ll get 10 tasks.


βš™οΈ Role of spark.default.parallelism

CaseDoes defaultParallelism Apply?
Reading files (CSV, Hive, Parquet)❌ No
sc.parallelize(range(100))βœ… Yes
Shuffle stage repartitioningβœ… Yes (as default number of output partitions)
GroupBy, Join, Aggregateβœ… Yes (controls shuffle partitions)
spark.conf.get("spark.default.parallelism")  # Often = total cores in cluster

πŸ§ͺ Example to Explore in Practice

df = spark.read.csv("/tmp/large.csv")
print("Partitions:", df.rdd.getNumPartitions())

# Force repartitioning to 20
df = df.repartition(20)
print("After repartition:", df.rdd.getNumPartitions())

πŸ” Conclusion

What Affects Task Count on ReadWhat Doesn’t
βœ… File size / HDFS block size❌ defaultParallelism
βœ… Number of partitions in Hive❌ Number of Spark executors
βœ… File format & compression❌ Temp views

Sure! Here’s a PySpark notebook (inline, Databricks-ready) that demonstrates:

  • How task count is influenced by file size and input splits
  • How .repartition() changes partition count
  • What defaultParallelism and shuffle.partitions are set to

πŸ““ Spark Parallelism Test Notebook

πŸ“Œ Objective:

Understand how Spark decides the number of tasks (partitions) when reading files and how repartitioning affects it.


βœ… 1. Spark Session Setup

from pyspark.sql import SparkSession

spark = SparkSession.builder.appName("ParallelismTest").getOrCreate()

βœ… 2. Create Sample CSV (~100MB)

from pyspark.sql.functions import monotonically_increasing_id

# ~10 million rows of dummy data
df = spark.range(10_000_000).withColumn("id", monotonically_increasing_id())
df = df.withColumn("value", (df.id % 1000).cast("string"))

# Write CSV to disk (~100MB uncompressed)
df.write.mode("overwrite").option("header", True).csv("/tmp/sample_100mb")

βœ… 3. Read Back CSV and Check Partitions (Tasks)

df_read = spark.read.option("header", True).csv("/tmp/sample_100mb")

print("πŸ”Ή Initial number of partitions (input splits):", df_read.rdd.getNumPartitions())

ℹ️ You can also see this in the Spark UI under Stage β†’ Tasks


βœ… 4. Repartition and Check Again

df_repart = df_read.repartition(16)

print("πŸ” After .repartition(16):", df_repart.rdd.getNumPartitions())

🧠 .repartition() does a full shuffle and redistributes data evenly into the requested number of partitions.


βœ… 5. Check Cluster Default Settings

print("βš™οΈ spark.default.parallelism:", spark.sparkContext.defaultParallelism)
print("βš™οΈ spark.sql.shuffle.partitions:", spark.conf.get("spark.sql.shuffle.partitions"))
  • default.parallelism – often equals total number of cores in cluster
  • shuffle.partitions – default number of output partitions after joins, groupBy, etc.

βœ… 6. Optional: Control Task Count by Chunking Files

# Try writing the same file in different chunk sizes
df.write.option("header", True).mode("overwrite").csv("/tmp/sample_small_chunks", maxRecordsPerFile=1000000)

df_small = spark.read.option("header", True).csv("/tmp/sample_small_chunks")
print("πŸ“ Partitions with multiple small files:", df_small.rdd.getNumPartitions())

βœ… Summary: What You Will Learn

ActionWhat It Controls
File Read (CSV/Parquet)Tasks = number of file splits
df.repartition(n)Rebalances partitions (shuffle)
spark.default.parallelismAffects parallelize, shuffles
File Size & LayoutControls natural task parallelism

Great question! The choice between .repartition() and .coalesce() in Spark has important performance implications depending on your use case.

Let’s break it down clearly:


βœ… Summary: repartition() vs coalesce()

Featurerepartition(n)coalesce(n)
πŸ” Shuffle involved?βœ… Yes – full shuffle❌ No – narrow transformation (no shuffle)
πŸ”Ό Increases partitions?βœ… Yes❌ Not efficient for increasing
πŸ”½ Reduces partitions?βœ… Yesβœ… Yes – ideal for reducing
🧠 Use caseBalance data across tasks (evenly)Reduce small files, avoid shuffle
🏁 PerformanceSlower (more network I/O)Faster (no shuffle)
πŸ’‘ Common ScenarioAfter wide transformation like joinBefore write to reduce file count

πŸ§ͺ In Our Case

We used:

df_repart = df_read.repartition(16)

Why?

  • Because we were demonstrating how Spark reshuffles data to change partition count, not just reduce it.
  • It’s a balanced partitioning, good for joins, aggregations, or if you’re increasing partition count.

❓ When Should You Use coalesce()?

df_small = df.repartition(200).coalesce(10)

Use coalesce() when:

  • You want to reduce the number of partitions
  • You’re about to write data and want fewer output files
  • You want to avoid a full shuffle

πŸ“Œ Practical Tip

GoalUse
Prepare for join or aggregationrepartition(n)
Writing to disk with fewer filescoalesce(n)
Minimize shuffle, reduce overheadcoalesce(n)
Need uniform task loadrepartition(n)

πŸ” Quick Code Comparison

# Full shuffle, uniform partitioning
df = df.repartition(20)

# Fast, no shuffle, may leave some partitions large
df = df.coalesce(4)

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