This is a fantastic deep-dive! Let’s answer your question clearly and technically:
β Question Recap:
If I read a 1 GB CSV file or a 1 GB Hive table into a DataFrame β
β DoesdefaultParallelism
apply?
β How are tasks created and executed in this case?
π§ Short Answer:
No,
defaultParallelism
does not directly control how Spark parallelizes file reads.
Here’s how it actually works:
Source Type | Partitioning Behavior |
---|---|
CSV / JSON / Parquet (from HDFS/S3) | Spark splits files into input splits using HDFS block size or internal logic |
Hive Tables | Spark uses the number of underlying file splits or partitions (if the table is partitioned) |
DefaultParallelism | Applies only when no better partitioning info is available, e.g., sc.parallelize() |
π§ Internal Mechanics β Step by Step
1. Reading a CSV file (e.g., 1 GB)
df = spark.read.csv("/path/to/file.csv")
- Spark internally uses Hadoop InputFormat to split this file into input splits.
- If the file is in HDFS and the block size is 128 MB, you’ll likely get:
- ~8 input splits β 8 tasks
- Each input split becomes one task in the initial stage (Stage 0).
You can check this via:
df.rdd.getNumPartitions()
β‘οΈ So, tasks = input splits, not controlled by defaultParallelism
.
2. Reading a Hive Table
df = spark.sql("SELECT * FROM my_table")
- Spark reads the underlying storage format (ORC, Parquet, etc.)
- If the table is partitioned, Spark will read files per partition.
- Number of files and their sizes decide how many tasks will run.
β‘οΈ If the table has 10 partitions and each is stored in a 100MB file, youβll get 10 tasks.
βοΈ Role of spark.default.parallelism
Case | Does defaultParallelism Apply? |
---|---|
Reading files (CSV, Hive, Parquet) | β No |
sc.parallelize(range(100)) | β Yes |
Shuffle stage repartitioning | β Yes (as default number of output partitions) |
GroupBy, Join, Aggregate | β Yes (controls shuffle partitions) |
spark.conf.get("spark.default.parallelism") # Often = total cores in cluster
π§ͺ Example to Explore in Practice
df = spark.read.csv("/tmp/large.csv")
print("Partitions:", df.rdd.getNumPartitions())
# Force repartitioning to 20
df = df.repartition(20)
print("After repartition:", df.rdd.getNumPartitions())
π Conclusion
What Affects Task Count on Read | What Doesn’t |
---|---|
β File size / HDFS block size | β defaultParallelism |
β Number of partitions in Hive | β Number of Spark executors |
β File format & compression | β Temp views |
Sure! Here’s a PySpark notebook (inline, Databricks-ready) that demonstrates:
- How task count is influenced by file size and input splits
- How
.repartition()
changes partition count - What
defaultParallelism
andshuffle.partitions
are set to
π Spark Parallelism Test Notebook
π Objective:
Understand how Spark decides the number of tasks (partitions) when reading files and how repartitioning affects it.
β 1. Spark Session Setup
from pyspark.sql import SparkSession
spark = SparkSession.builder.appName("ParallelismTest").getOrCreate()
β 2. Create Sample CSV (~100MB)
from pyspark.sql.functions import monotonically_increasing_id
# ~10 million rows of dummy data
df = spark.range(10_000_000).withColumn("id", monotonically_increasing_id())
df = df.withColumn("value", (df.id % 1000).cast("string"))
# Write CSV to disk (~100MB uncompressed)
df.write.mode("overwrite").option("header", True).csv("/tmp/sample_100mb")
β 3. Read Back CSV and Check Partitions (Tasks)
df_read = spark.read.option("header", True).csv("/tmp/sample_100mb")
print("πΉ Initial number of partitions (input splits):", df_read.rdd.getNumPartitions())
βΉοΈ You can also see this in the Spark UI under Stage β Tasks
β 4. Repartition and Check Again
df_repart = df_read.repartition(16)
print("π After .repartition(16):", df_repart.rdd.getNumPartitions())
π§ .repartition()
does a full shuffle and redistributes data evenly into the requested number of partitions.
β 5. Check Cluster Default Settings
print("βοΈ spark.default.parallelism:", spark.sparkContext.defaultParallelism)
print("βοΈ spark.sql.shuffle.partitions:", spark.conf.get("spark.sql.shuffle.partitions"))
default.parallelism
β often equals total number of cores in clustershuffle.partitions
β default number of output partitions after joins, groupBy, etc.
β 6. Optional: Control Task Count by Chunking Files
# Try writing the same file in different chunk sizes
df.write.option("header", True).mode("overwrite").csv("/tmp/sample_small_chunks", maxRecordsPerFile=1000000)
df_small = spark.read.option("header", True).csv("/tmp/sample_small_chunks")
print("π Partitions with multiple small files:", df_small.rdd.getNumPartitions())
β Summary: What You Will Learn
Action | What It Controls |
---|---|
File Read (CSV/Parquet) | Tasks = number of file splits |
df.repartition(n) | Rebalances partitions (shuffle) |
spark.default.parallelism | Affects parallelize , shuffles |
File Size & Layout | Controls natural task parallelism |
Great question! The choice between .repartition()
and .coalesce()
in Spark has important performance implications depending on your use case.
Letβs break it down clearly:
β
Summary: repartition()
vs coalesce()
Feature | repartition(n) | coalesce(n) |
---|---|---|
π Shuffle involved? | β Yes β full shuffle | β No β narrow transformation (no shuffle) |
πΌ Increases partitions? | β Yes | β Not efficient for increasing |
π½ Reduces partitions? | β Yes | β Yes β ideal for reducing |
π§ Use case | Balance data across tasks (evenly) | Reduce small files, avoid shuffle |
π Performance | Slower (more network I/O) | Faster (no shuffle) |
π‘ Common Scenario | After wide transformation like join | Before write to reduce file count |
π§ͺ In Our Case
We used:
df_repart = df_read.repartition(16)
Why?
- Because we were demonstrating how Spark reshuffles data to change partition count, not just reduce it.
- Itβs a balanced partitioning, good for joins, aggregations, or if you’re increasing partition count.
β When Should You Use coalesce()
?
df_small = df.repartition(200).coalesce(10)
Use coalesce()
when:
- You want to reduce the number of partitions
- Youβre about to write data and want fewer output files
- You want to avoid a full shuffle
π Practical Tip
Goal | Use |
---|---|
Prepare for join or aggregation | repartition(n) |
Writing to disk with fewer files | coalesce(n) |
Minimize shuffle, reduce overhead | coalesce(n) |
Need uniform task load | repartition(n) |
π Quick Code Comparison
# Full shuffle, uniform partitioning
df = df.repartition(20)
# Fast, no shuffle, may leave some partitions large
df = df.coalesce(4)
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